5+3(y-4)=2(y+1)

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Solution for 5+3(y-4)=2(y+1) equation:


Simplifying
5 + 3(y + -4) = 2(y + 1)

Reorder the terms:
5 + 3(-4 + y) = 2(y + 1)
5 + (-4 * 3 + y * 3) = 2(y + 1)
5 + (-12 + 3y) = 2(y + 1)

Combine like terms: 5 + -12 = -7
-7 + 3y = 2(y + 1)

Reorder the terms:
-7 + 3y = 2(1 + y)
-7 + 3y = (1 * 2 + y * 2)
-7 + 3y = (2 + 2y)

Solving
-7 + 3y = 2 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-7 + 3y + -2y = 2 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-7 + 1y = 2 + 2y + -2y

Combine like terms: 2y + -2y = 0
-7 + 1y = 2 + 0
-7 + 1y = 2

Add '7' to each side of the equation.
-7 + 7 + 1y = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 1y = 2 + 7
1y = 2 + 7

Combine like terms: 2 + 7 = 9
1y = 9

Divide each side by '1'.
y = 9

Simplifying
y = 9

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