5+3(y-4)=4y+10

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Solution for 5+3(y-4)=4y+10 equation: 



5+3(y-4)=4y+10

We move all terms to the left:

5+3(y-4)-(4y+10)=0

We multiply parentheses

3y-(4y+10)-12+5=0

We get rid of parentheses

3y-4y-10-12+5=0

We add all the numbers together, and all the variables

-1y-17=0

We move all terms containing y to the left, all other terms to the right

-y=17

y=17/-1

y=-17

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