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5+3(y-4)=5(y+2)-7
We move all terms to the left:
5+3(y-4)-(5(y+2)-7)=0
We multiply parentheses
3y-(5(y+2)-7)-12+5=0
We calculate terms in parentheses: -(5(y+2)-7), so:We add all the numbers together, and all the variables
5(y+2)-7
We multiply parentheses
5y+10-7
We add all the numbers together, and all the variables
5y+3
Back to the equation:
-(5y+3)
3y-(5y+3)-7=0
We get rid of parentheses
3y-5y-3-7=0
We add all the numbers together, and all the variables
-2y-10=0
We move all terms containing y to the left, all other terms to the right
-2y=10
y=10/-2
y=-5
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