5+3(y-4)=5(y+2)-8

Solution for 5+3(y-4)=5(y+2)-8 equation:

5+3(y-4)=5(y+2)-8

We move all terms to the left:

5+3(y-4)-(5(y+2)-8)=0

We multiply parentheses

3y-(5(y+2)-8)-12+5=0


We calculate terms in parentheses: -(5(y+2)-8), so:

5(y+2)-8

We multiply parentheses

5y+10-8

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)


We add all the numbers together, and all the variables

3y-(5y+2)-7=0

We get rid of parentheses

3y-5y-2-7=0

We add all the numbers together, and all the variables

-2y-9=0

We move all terms containing y to the left, all other terms to the right

-2y=9

y=9/-2

y=-4+1/2