5+3(y-4)=5(y+2)-y.

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Solution for 5+3(y-4)=5(y+2)-y. equation: 



5+3(y-4)=5(y+2)-y.

We move all terms to the left:

5+3(y-4)-(5(y+2)-y.)=0

We multiply parentheses

3y-(5(y+2)-y.)-12+5=0



We calculate terms in parentheses: -(5(y+2)-y.), so:

5(y+2)-y.

We multiply parentheses

5y-y.+10

Back to the equation:

-(5y-y.+10)



We add all the numbers together, and all the variables

3y-(5y-y.+10)-7=0

We get rid of parentheses

3y-5y+y.-10-7=0

We add all the numbers together, and all the variables

-2y+y.-17=0

We move all terms containing y to the left, all other terms to the right

-2y+y.=17

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