5+3(y-4)=5(y+2)=y

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Solution for 5+3(y-4)=5(y+2)=y equation: 



5+3(y-4)=5(y+2)=y

We move all terms to the left:

5+3(y-4)-(5(y+2))=0

We multiply parentheses

3y-(5(y+2))-12+5=0



We calculate terms in parentheses: -(5(y+2)), so:

5(y+2)

We multiply parentheses

5y+10

Back to the equation:

-(5y+10)



We add all the numbers together, and all the variables

3y-(5y+10)-7=0

We get rid of parentheses

3y-5y-10-7=0

We add all the numbers together, and all the variables

-2y-17=0

We move all terms containing y to the left, all other terms to the right

-2y=17

y=17/-2

y=-8+1/2

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