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5+3/5b=7/10b=

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Solution for 5+3/5b=7/10b= equation: 



5+3/5b=7/10b=

We move all terms to the left:

5+3/5b-(7/10b)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R





Domain of the equation: 10b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

3/5b-(+7/10b)+5=0

We get rid of parentheses

3/5b-7/10b+5=0

We calculate fractions


30b/50b^2+(-35b)/50b^2+5=0

We multiply all the terms by the denominator


30b+(-35b)+5*50b^2=0

Wy multiply elements

250b^2+30b+(-35b)=0

We get rid of parentheses

250b^2+30b-35b=0

We add all the numbers together, and all the variables

250b^2-5b=0

a = 250; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·250·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
b_{1}=\frac{-b-\sqrt{\Delta}}{2a}
b_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{25}=5


b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*250}=\frac{0}{500}
=0



b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*250}=\frac{10}{500}
=1/50

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