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5+3/5x=6-2/3x
We move all terms to the left:
5+3/5x-(6-2/3x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/5x-(-2/3x+6)+5=0
We get rid of parentheses
3/5x+2/3x-6+5=0
We calculate fractions
9x/15x^2+10x/15x^2-6+5=0
We add all the numbers together, and all the variables
9x/15x^2+10x/15x^2-1=0
We multiply all the terms by the denominator
9x+10x-1*15x^2=0
We add all the numbers together, and all the variables
19x-1*15x^2=0
Wy multiply elements
-15x^2+19x=0
a = -15; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-15)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-15}=\frac{-38}{-30} =1+4/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-15}=\frac{0}{-30} =0 $
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