5+3x(x-2)+8=10

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Solution for 5+3x(x-2)+8=10 equation: 



5+3x(x-2)+8=10

We move all terms to the left:

5+3x(x-2)+8-(10)=0

We add all the numbers together, and all the variables

3x(x-2)+3=0

We multiply parentheses

3x^2-6x+3=0

a = 3; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{6}=1$

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