5+3x-x=1x(x+3)

Solution for 5+3x-x=1x(x+3) equation:

5+3x-x=1x(x+3)

We move all terms to the left:

5+3x-x-(1x(x+3))=0

We add all the numbers together, and all the variables

2x-(1x(x+3))+5=0


We calculate terms in parentheses: -(1x(x+3)), so:

1x(x+3)

We multiply parentheses

x^2+3x

Back to the equation:

-(x^2+3x)


We get rid of parentheses

-x^2+2x-3x+5=0

We add all the numbers together, and all the variables

-1x^2-1x+5=0

a = -1; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·(-1)·5
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{21}}{2*-1}=\frac{1-\sqrt{21}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{21}}{2*-1}=\frac{1+\sqrt{21}}{-2}
$