5+3x=26x2

Solution for 5+3x=26x2 equation:

5+3x=26x^2

We move all terms to the left:

5+3x-(26x^2)=0

determiningTheFunctionDomain
-26x^2+3x+5=0

a = -26; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-26)·5
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-23}{2*-26}=\frac{-26}{-52}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+23}{2*-26}=\frac{20}{-52}
=-5/13
$