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5+3x=7+(x+3)
We move all terms to the left:
5+3x-(7+(x+3))=0
We calculate terms in parentheses: -(7+(x+3)), so:We get rid of parentheses
7+(x+3)
determiningTheFunctionDomain (x+3)+7
We get rid of parentheses
x+3+7
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
3x-x-10+5=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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