5+4(3x-5)+4x-2(4-x)=18(x+2)

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Solution for 5+4(3x-5)+4x-2(4-x)=18(x+2) equation: 



5+4(3x-5)+4x-2(4-x)=18(x+2)

We move all terms to the left:

5+4(3x-5)+4x-2(4-x)-(18(x+2))=0

We add all the numbers together, and all the variables

4(3x-5)+4x-2(-1x+4)-(18(x+2))+5=0

We add all the numbers together, and all the variables

4x+4(3x-5)-2(-1x+4)-(18(x+2))+5=0

We multiply parentheses

4x+12x+2x-(18(x+2))-20-8+5=0



We calculate terms in parentheses: -(18(x+2)), so:

18(x+2)

We multiply parentheses

18x+36

Back to the equation:

-(18x+36)



We add all the numbers together, and all the variables

18x-(18x+36)-23=0

We get rid of parentheses

18x-18x-36-23=0

We add all the numbers together, and all the variables

-59!=0

There is no solution for this equation

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