5+4(t-2)=(t+7)+1

Solution for 5+4(t-2)=(t+7)+1 equation:

5+4(t-2)=(t+7)+1

We move all terms to the left:

5+4(t-2)-((t+7)+1)=0

We multiply parentheses

4t-((t+7)+1)-8+5=0


We calculate terms in parentheses: -((t+7)+1), so:

(t+7)+1

We get rid of parentheses

t+7+1

We add all the numbers together, and all the variables

t+8

Back to the equation:

-(t+8)


We add all the numbers together, and all the variables

4t-(t+8)-3=0

We get rid of parentheses

4t-t-8-3=0

We add all the numbers together, and all the variables

3t-11=0

We move all terms containing t to the left, all other terms to the right

3t=11

t=11/3

t=3+2/3