5+4(t-2)=2(t+7)+1

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Solution for 5+4(t-2)=2(t+7)+1 equation:


Simplifying
5 + 4(t + -2) = 2(t + 7) + 1

Reorder the terms:
5 + 4(-2 + t) = 2(t + 7) + 1
5 + (-2 * 4 + t * 4) = 2(t + 7) + 1
5 + (-8 + 4t) = 2(t + 7) + 1

Combine like terms: 5 + -8 = -3
-3 + 4t = 2(t + 7) + 1

Reorder the terms:
-3 + 4t = 2(7 + t) + 1
-3 + 4t = (7 * 2 + t * 2) + 1
-3 + 4t = (14 + 2t) + 1

Reorder the terms:
-3 + 4t = 14 + 1 + 2t

Combine like terms: 14 + 1 = 15
-3 + 4t = 15 + 2t

Solving
-3 + 4t = 15 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-3 + 4t + -2t = 15 + 2t + -2t

Combine like terms: 4t + -2t = 2t
-3 + 2t = 15 + 2t + -2t

Combine like terms: 2t + -2t = 0
-3 + 2t = 15 + 0
-3 + 2t = 15

Add '3' to each side of the equation.
-3 + 3 + 2t = 15 + 3

Combine like terms: -3 + 3 = 0
0 + 2t = 15 + 3
2t = 15 + 3

Combine like terms: 15 + 3 = 18
2t = 18

Divide each side by '2'.
t = 9

Simplifying
t = 9

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