5+4(x-2)=2(t+7)+1

Solution for 5+4(x-2)=2(t+7)+1 equation:

Simplifying
5 + 4(x + -2) = 2(t + 7) + 1

Reorder the terms:
5 + 4(-2 + x) = 2(t + 7) + 1
5 + (-2 * 4 + x * 4) = 2(t + 7) + 1
5 + (-8 + 4x) = 2(t + 7) + 1

Combine like terms: 5 + -8 = -3
-3 + 4x = 2(t + 7) + 1

Reorder the terms:
-3 + 4x = 2(7 + t) + 1
-3 + 4x = (7 * 2 + t * 2) + 1
-3 + 4x = (14 + 2t) + 1

Reorder the terms:
-3 + 4x = 14 + 1 + 2t

Combine like terms: 14 + 1 = 15
-3 + 4x = 15 + 2t

Solving
-3 + 4x = 15 + 2t

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 4x = 15 + 3 + 2t

Combine like terms: -3 + 3 = 0
0 + 4x = 15 + 3 + 2t
4x = 15 + 3 + 2t

Combine like terms: 15 + 3 = 18
4x = 18 + 2t

Divide each side by '4'.
x = 4.5 + 0.5t

Simplifying
x = 4.5 + 0.5t