5+4(y+2)=2y-3(y+4)

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Solution for 5+4(y+2)=2y-3(y+4) equation: 



5+4(y+2)=2y-3(y+4)

We move all terms to the left:

5+4(y+2)-(2y-3(y+4))=0

We multiply parentheses

4y-(2y-3(y+4))+8+5=0



We calculate terms in parentheses: -(2y-3(y+4)), so:

2y-3(y+4)

We multiply parentheses

2y-3y-12

We add all the numbers together, and all the variables

-1y-12

Back to the equation:

-(-1y-12)



We add all the numbers together, and all the variables

4y-(-1y-12)+13=0

We get rid of parentheses

4y+1y+12+13=0

We add all the numbers together, and all the variables

5y+25=0

We move all terms containing y to the left, all other terms to the right

5y=-25

y=-25/5

y=-5

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