5+4b=-5-5(2b-2)

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Solution for 5+4b=-5-5(2b-2) equation: 



5+4b=-5-5(2b-2)

We move all terms to the left:

5+4b-(-5-5(2b-2))=0



We calculate terms in parentheses: -(-5-5(2b-2)), so:

-5-5(2b-2)

determiningTheFunctionDomain
-5(2b-2)-5

We multiply parentheses

-10b+10-5

We add all the numbers together, and all the variables

-10b+5

Back to the equation:

-(-10b+5)



We get rid of parentheses

4b+10b-5+5=0

We add all the numbers together, and all the variables

14b=0

b=0/14

b=0

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