5+5(2x-12)=3(x-1)-38

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Solution for 5+5(2x-12)=3(x-1)-38 equation: 



5+5(2x-12)=3(x-1)-38

We move all terms to the left:

5+5(2x-12)-(3(x-1)-38)=0

We multiply parentheses

10x-(3(x-1)-38)-60+5=0



We calculate terms in parentheses: -(3(x-1)-38), so:

3(x-1)-38

We multiply parentheses

3x-3-38

We add all the numbers together, and all the variables

3x-41

Back to the equation:

-(3x-41)



We add all the numbers together, and all the variables

10x-(3x-41)-55=0

We get rid of parentheses

10x-3x+41-55=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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