5+5(2x-12)=3(x-1)-38

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Solution for 5+5(2x-12)=3(x-1)-38 equation:



5+5(2x-12)=3(x-1)-38
We move all terms to the left:
5+5(2x-12)-(3(x-1)-38)=0
We multiply parentheses
10x-(3(x-1)-38)-60+5=0
We calculate terms in parentheses: -(3(x-1)-38), so:
3(x-1)-38
We multiply parentheses
3x-3-38
We add all the numbers together, and all the variables
3x-41
Back to the equation:
-(3x-41)
We add all the numbers together, and all the variables
10x-(3x-41)-55=0
We get rid of parentheses
10x-3x+41-55=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2

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