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5+5x=-4+1/2x
We move all terms to the left:
5+5x-(-4+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(1/2x-4)+5=0
We get rid of parentheses
5x-1/2x+4+5=0
We multiply all the terms by the denominator
5x*2x+4*2x+5*2x-1=0
Wy multiply elements
10x^2+8x+10x-1=0
We add all the numbers together, and all the variables
10x^2+18x-1=0
a = 10; b = 18; c = -1;
Δ = b2-4ac
Δ = 182-4·10·(-1)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{91}}{2*10}=\frac{-18-2\sqrt{91}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{91}}{2*10}=\frac{-18+2\sqrt{91}}{20} $
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