5+6(6y+2)=3(2-6y)-7

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Solution for 5+6(6y+2)=3(2-6y)-7 equation: 



5+6(6y+2)=3(2-6y)-7

We move all terms to the left:

5+6(6y+2)-(3(2-6y)-7)=0

We add all the numbers together, and all the variables

6(6y+2)-(3(-6y+2)-7)+5=0

We multiply parentheses

36y-(3(-6y+2)-7)+12+5=0



We calculate terms in parentheses: -(3(-6y+2)-7), so:

3(-6y+2)-7

We multiply parentheses

-18y+6-7

We add all the numbers together, and all the variables

-18y-1

Back to the equation:

-(-18y-1)



We add all the numbers together, and all the variables

36y-(-18y-1)+17=0

We get rid of parentheses

36y+18y+1+17=0

We add all the numbers together, and all the variables

54y+18=0

We move all terms containing y to the left, all other terms to the right

54y=-18

y=-18/54

y=-1/3

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