5+6x+3=4(x-2)+20

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Solution for 5+6x+3=4(x-2)+20 equation: 



5+6x+3=4(x-2)+20

We move all terms to the left:

5+6x+3-(4(x-2)+20)=0

We add all the numbers together, and all the variables

6x-(4(x-2)+20)+8=0



We calculate terms in parentheses: -(4(x-2)+20), so:

4(x-2)+20

We multiply parentheses

4x-8+20

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

6x-4x-12+8=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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