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5+x2=2
We move all terms to the left:
5+x2-(2)=0
We add all the numbers together, and all the variables
x^2+3=0
a = 1; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·1·3
Δ = -12
Delta is less than zero, so there is no solution for the equation
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