5+x2=250

Solution for 5+x2=250 equation:

5+x2=250

We move all terms to the left:

5+x2-(250)=0

We add all the numbers together, and all the variables

x^2-245=0

a = 1; b = 0; c = -245;
Δ = b2-4ac
Δ = 02-4·1·(-245)
Δ = 980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{980}=\sqrt{196*5}=\sqrt{196}*\sqrt{5}=14\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{5}}{2*1}=\frac{0-14\sqrt{5}}{2}
=-\frac{14\sqrt{5}}{2}
=-7\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{5}}{2*1}=\frac{0+14\sqrt{5}}{2}
=\frac{14\sqrt{5}}{2}
=7\sqrt{5}
$