5-((1/2)n)=21

Solution for 5-((1/2)n)=21 equation:

5-((1/2)n)=21

We move all terms to the left:

5-((1/2)n)-(21)=0


Domain of the equation: 2)n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

-((+1/2)n)+5-21=0

We add all the numbers together, and all the variables

-((+1/2)n)-16=0

We multiply all the terms by the denominator


-((+1-16*2)n)=0


We calculate terms in parentheses: -((+1-16*2)n), so:

(+1-16*2)n

We add all the numbers together, and all the variables

(-31)n

We multiply parentheses

-31n

Back to the equation:

-(-31n)


We get rid of parentheses

31n=0

n=0/31

n=0

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