5-((3-2x)/2)=((4x+5)/5)

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Solution for 5-((3-2x)/2)=((4x+5)/5) equation: 


x in (-oo:+oo)

5-((3-(2*x))/2) = (4*x+5)/5 // - (4*x+5)/5

5-((3-(2*x))/2)-((4*x+5)/5) = 0

5-((3-2*x)/2)-((4*x+5)/5) = 0

(-1*(3-2*x))/2+(-1*(4*x+5))/5+5 = 0

(-1*5*(3-2*x))/(2*5)+(-1*2*(4*x+5))/(2*5)+(2*5^2)/(2*5) = 0

2*5^2-1*5*(3-2*x)-1*2*(4*x+5) = 0

2*x-25+50 = 0

2*x+25 = 0

(2*x+25)/(2*5) = 0

(2*x+25)/(2*5) = 0 // * 2*5

2*x+25 = 0

2*x+25 = 0 // - 25

2*x = -25 // : 2

x = -25/2

x = -25/2

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