5-((3a-4)/(5))=((7-2a)/(2))

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Solution for 5-((3a-4)/(5))=((7-2a)/(2)) equation: 


a in (-oo:+oo)

5-((3*a-4)/5) = (7-(2*a))/2 // - (7-(2*a))/2

5-((3*a-4)/5)-((7-(2*a))/2) = 0

5-((3*a-4)/5)-((7-2*a)/2) = 0

(-1*(3*a-4))/5+(-1*(7-2*a))/2+5 = 0

(-1*2*(3*a-4))/(2*5)+(-1*5*(7-2*a))/(2*5)+(2*5^2)/(2*5) = 0

2*5^2-1*2*(3*a-4)-1*5*(7-2*a) = 0

4*a-27+50 = 0

4*a+23 = 0

(4*a+23)/(2*5) = 0

(4*a+23)/(2*5) = 0 // * 2*5

4*a+23 = 0

4*a+23 = 0 // - 23

4*a = -23 // : 4

a = -23/4

a = -23/4

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