5-((6x-4)/5)=x-3

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Solution for 5-((6x-4)/5)=x-3 equation: 



5-((6x-4)/5)=x-3

We move all terms to the left:

5-((6x-4)/5)-(x-3)=0

We get rid of parentheses

-((6x-4)/5)-x+3+5=0

We multiply all the terms by the denominator


-((6x-4)-x*5)+3*5)+5*5)=0



We calculate terms in parentheses: -((6x-4)-x*5), so:

(6x-4)-x*5

Wy multiply elements

(6x-4)-5x

We get rid of parentheses

6x-5x-4

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)



We add all the numbers together, and all the variables

-(x-4)=0

We get rid of parentheses

-x+4=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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