5-(-x-4)=3(x+2)

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Solution for 5-(-x-4)=3(x+2) equation:



5-(-x-4)=3(x+2)
We move all terms to the left:
5-(-x-4)-(3(x+2))=0
We add all the numbers together, and all the variables
-(-1x-4)-(3(x+2))+5=0
We get rid of parentheses
1x-(3(x+2))+4+5=0
We calculate terms in parentheses: -(3(x+2)), so:
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
We add all the numbers together, and all the variables
x-(3x+6)+9=0
We get rid of parentheses
x-3x-6+9=0
We add all the numbers together, and all the variables
-2x+3=0
We move all terms containing x to the left, all other terms to the right
-2x=-3
x=-3/-2
x=1+1/2

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