5-(1+2b)=6b+28

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Solution for 5-(1+2b)=6b+28 equation: 



5-(1+2b)=6b+28

We move all terms to the left:

5-(1+2b)-(6b+28)=0

We add all the numbers together, and all the variables

-(2b+1)-(6b+28)+5=0

We get rid of parentheses

-2b-6b-1-28+5=0

We add all the numbers together, and all the variables

-8b-24=0

We move all terms containing b to the left, all other terms to the right

-8b=24

b=24/-8

b=-3

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