5-(2x+5)+3x=10-7(3x-2)-35

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Solution for 5-(2x+5)+3x=10-7(3x-2)-35 equation: 



5-(2x+5)+3x=10-7(3x-2)-35

We move all terms to the left:

5-(2x+5)+3x-(10-7(3x-2)-35)=0

We add all the numbers together, and all the variables

3x-(2x+5)-(10-7(3x-2)-35)+5=0

We get rid of parentheses

3x-2x-(10-7(3x-2)-35)-5+5=0



We calculate terms in parentheses: -(10-7(3x-2)-35), so:

10-7(3x-2)-35

determiningTheFunctionDomain
-7(3x-2)+10-35

We add all the numbers together, and all the variables

-7(3x-2)-25

We multiply parentheses

-21x+14-25

We add all the numbers together, and all the variables

-21x-11

Back to the equation:

-(-21x-11)



We add all the numbers together, and all the variables

x-(-21x-11)=0

We get rid of parentheses

x+21x+11=0

We add all the numbers together, and all the variables

22x+11=0

We move all terms containing x to the left, all other terms to the right

22x=-11

x=-11/22

x=-1/2

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