5-(2x-1)=(x+1)-8

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Solution for 5-(2x-1)=(x+1)-8 equation: 



5-(2x-1)=(x+1)-8

We move all terms to the left:

5-(2x-1)-((x+1)-8)=0

We get rid of parentheses

-2x-((x+1)-8)+1+5=0



We calculate terms in parentheses: -((x+1)-8), so:

(x+1)-8

We get rid of parentheses

x+1-8

We add all the numbers together, and all the variables

x-7

Back to the equation:

-(x-7)



We add all the numbers together, and all the variables

-2x-(x-7)+6=0

We get rid of parentheses

-2x-x+7+6=0

We add all the numbers together, and all the variables

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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