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5-(2x/5)=1+(4/5)x
We move all terms to the left:
5-(2x/5)-(1+(4/5)x)=0
Domain of the equation: 5)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2x/5)-(1+(+4/5)x)+5=0
We get rid of parentheses
-2x/5-(1+(+4/5)x)+5=0
We calculate fractions
5!=0
There is no solution for this equation
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