5-(3/4)s=-1

Solution for 5-(3/4)s=-1 equation:

5-(3/4)s=-1

We move all terms to the left:

5-(3/4)s-(-1)=0


Domain of the equation: 4)s!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

-(+3/4)s+5-(-1)=0

We add all the numbers together, and all the variables

-(+3/4)s+6=0

We multiply parentheses

-3s^2+6=0

a = -3; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-3)·6
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-3}=\frac{0-6\sqrt{2}}{-6}
=-\frac{6\sqrt{2}}{-6}
=-\frac{\sqrt{2}}{-1}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-3}=\frac{0+6\sqrt{2}}{-6}
=\frac{6\sqrt{2}}{-6}
=\frac{\sqrt{2}}{-1}
$