5-(3c+4)=4(c+6)+c

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Solution for 5-(3c+4)=4(c+6)+c equation: 



5-(3c+4)=4(c+6)+c

We move all terms to the left:

5-(3c+4)-(4(c+6)+c)=0

We get rid of parentheses

-3c-(4(c+6)+c)-4+5=0



We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)



We add all the numbers together, and all the variables

-3c-(5c+24)+1=0

We get rid of parentheses

-3c-5c-24+1=0

We add all the numbers together, and all the variables

-8c-23=0

We move all terms containing c to the left, all other terms to the right

-8c=23

c=23/-8

c=-2+7/8

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