5-(3x-2(x+3))=4

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Solution for 5-(3x-2(x+3))=4 equation: 



5-(3x-2(x+3))=4

We move all terms to the left:

5-(3x-2(x+3))-(4)=0

We add all the numbers together, and all the variables

-(3x-2(x+3))+1=0



We calculate terms in parentheses: -(3x-2(x+3)), so:

3x-2(x+3)

We multiply parentheses

3x-2x-6

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We get rid of parentheses

-x+6+1=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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