5-(3x-2)=4(x+5)-4

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Solution for 5-(3x-2)=4(x+5)-4 equation: 



5-(3x-2)=4(x+5)-4

We move all terms to the left:

5-(3x-2)-(4(x+5)-4)=0

We get rid of parentheses

-3x-(4(x+5)-4)+2+5=0



We calculate terms in parentheses: -(4(x+5)-4), so:

4(x+5)-4

We multiply parentheses

4x+20-4

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

-3x-(4x+16)+7=0

We get rid of parentheses

-3x-4x-16+7=0

We add all the numbers together, and all the variables

-7x-9=0

We move all terms containing x to the left, all other terms to the right

-7x=9

x=9/-7

x=-1+2/7

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