5-(3x-4)/5=(7-2x)/2

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Solution for 5-(3x-4)/5=(7-2x)/2 equation: 


x in (-oo:+oo)

5-((3*x-4)/5) = (7-(2*x))/2 // - (7-(2*x))/2

5-((3*x-4)/5)-((7-(2*x))/2) = 0

5-((3*x-4)/5)-((7-2*x)/2) = 0

(-1*(3*x-4))/5+(-1*(7-2*x))/2+5 = 0

(-1*2*(3*x-4))/(2*5)+(-1*5*(7-2*x))/(2*5)+(2*5^2)/(2*5) = 0

2*5^2-1*2*(3*x-4)-1*5*(7-2*x) = 0

4*x-27+50 = 0

4*x+23 = 0

(4*x+23)/(2*5) = 0

(4*x+23)/(2*5) = 0 // * 2*5

4*x+23 = 0

4*x+23 = 0 // - 23

4*x = -23 // : 4

x = -23/4

x = -23/4

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