5-(3z-2)=2z+2

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Solution for 5-(3z-2)=2z+2 equation: 



5-(3z-2)=2z+2

We move all terms to the left:

5-(3z-2)-(2z+2)=0

We get rid of parentheses

-3z-2z+2-2+5=0

We add all the numbers together, and all the variables

-5z+5=0

We move all terms containing z to the left, all other terms to the right

-5z=-5

z=-5/-5

z=1

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