5-(4+3)=-1+2(t-3)

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Solution for 5-(4+3)=-1+2(t-3) equation: 



5-(4+3)=-1+2(t-3)

We move all terms to the left:

5-(4+3)-(-1+2(t-3))=0

We add all the numbers together, and all the variables

-(-1+2(t-3))+5-7=0

We add all the numbers together, and all the variables

-(-1+2(t-3))-2=0



We calculate terms in parentheses: -(-1+2(t-3)), so:

-1+2(t-3)

determiningTheFunctionDomain
2(t-3)-1

We multiply parentheses

2t-6-1

We add all the numbers together, and all the variables

2t-7

Back to the equation:

-(2t-7)



We get rid of parentheses

-2t+7-2=0

We add all the numbers together, and all the variables

-2t+5=0

We move all terms containing t to the left, all other terms to the right

-2t=-5

t=-5/-2

t=2+1/2

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