5-(4-2x)2/3=1

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Solution for 5-(4-2x)2/3=1 equation: 


x in (-oo:+oo)

5-(((4-(2*x))^2)/3) = 1 // - 1

5-(((4-(2*x))^2)/3)-1 = 0

5-(((4-2*x)^2)/3)-1 = 0

(-1*(4-2*x)^2)/3-1+5 = 0

(-1*(4-2*x)^2)/3+(-1*3)/3+(3*5)/3 = 0

3*5-1*(4-2*x)^2-1*3 = 0

16*x-4*x^2-19+15 = 0

16*x-4*x^2-4 = 0

16*x-4*x^2-4 = 0

4*(4*x-x^2-1) = 0

4*x-x^2-1 = 0

DELTA = 4^2-(-1*(-1)*4)

DELTA = 12

DELTA > 0

x = (12^(1/2)-4)/(-1*2) or x = (-12^(1/2)-4)/(-1*2)

x = (2*3^(1/2)-4)/(-2) or x = (-2*3^(1/2)-4)/(-2)

4*(x-((2*3^(1/2)-4)/(-2)))*(x-((-2*3^(1/2)-4)/(-2))) = 0

(4*(x-((2*3^(1/2)-4)/(-2)))*(x-((-2*3^(1/2)-4)/(-2))))/3 = 0

(4*(x-((2*3^(1/2)-4)/(-2)))*(x-((-2*3^(1/2)-4)/(-2))))/3 = 0 // * 3

4*(x-((2*3^(1/2)-4)/(-2)))*(x-((-2*3^(1/2)-4)/(-2))) = 0

( 4 )

4 = 0

x belongs to the empty set

( x-((-2*3^(1/2)-4)/(-2)) )

x-((-2*3^(1/2)-4)/(-2)) = 0 // + (-2*3^(1/2)-4)/(-2)

x = (-2*3^(1/2)-4)/(-2)

( x-((2*3^(1/2)-4)/(-2)) )

x-((2*3^(1/2)-4)/(-2)) = 0 // + (2*3^(1/2)-4)/(-2)

x = (2*3^(1/2)-4)/(-2)

x in { (-2*3^(1/2)-4)/(-2), (2*3^(1/2)-4)/(-2) }

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