5-(4r+1)-r=4(2r-3)+15

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Solution for 5-(4r+1)-r=4(2r-3)+15 equation:



5-(4r+1)-r=4(2r-3)+15
We move all terms to the left:
5-(4r+1)-r-(4(2r-3)+15)=0
We add all the numbers together, and all the variables
-1r-(4r+1)-(4(2r-3)+15)+5=0
We get rid of parentheses
-1r-4r-(4(2r-3)+15)-1+5=0
We calculate terms in parentheses: -(4(2r-3)+15), so:
4(2r-3)+15
We multiply parentheses
8r-12+15
We add all the numbers together, and all the variables
8r+3
Back to the equation:
-(8r+3)
We add all the numbers together, and all the variables
-5r-(8r+3)+4=0
We get rid of parentheses
-5r-8r-3+4=0
We add all the numbers together, and all the variables
-13r+1=0
We move all terms containing r to the left, all other terms to the right
-13r=-1
r=-1/-13
r=1/13

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