5-(b+1)-3(b-2)=0

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Solution for 5-(b+1)-3(b-2)=0 equation:


Simplifying
5 + -1(b + 1) + -3(b + -2) = 0

Reorder the terms:
5 + -1(1 + b) + -3(b + -2) = 0
5 + (1 * -1 + b * -1) + -3(b + -2) = 0
5 + (-1 + -1b) + -3(b + -2) = 0

Reorder the terms:
5 + -1 + -1b + -3(-2 + b) = 0
5 + -1 + -1b + (-2 * -3 + b * -3) = 0
5 + -1 + -1b + (6 + -3b) = 0

Reorder the terms:
5 + -1 + 6 + -1b + -3b = 0

Combine like terms: 5 + -1 = 4
4 + 6 + -1b + -3b = 0

Combine like terms: 4 + 6 = 10
10 + -1b + -3b = 0

Combine like terms: -1b + -3b = -4b
10 + -4b = 0

Solving
10 + -4b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -4b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -4b = 0 + -10
-4b = 0 + -10

Combine like terms: 0 + -10 = -10
-4b = -10

Divide each side by '-4'.
b = 2.5

Simplifying
b = 2.5

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