5-(b+2)-3(b-2)=0

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Solution for 5-(b+2)-3(b-2)=0 equation:


Simplifying
5 + -1(b + 2) + -3(b + -2) = 0

Reorder the terms:
5 + -1(2 + b) + -3(b + -2) = 0
5 + (2 * -1 + b * -1) + -3(b + -2) = 0
5 + (-2 + -1b) + -3(b + -2) = 0

Reorder the terms:
5 + -2 + -1b + -3(-2 + b) = 0
5 + -2 + -1b + (-2 * -3 + b * -3) = 0
5 + -2 + -1b + (6 + -3b) = 0

Reorder the terms:
5 + -2 + 6 + -1b + -3b = 0

Combine like terms: 5 + -2 = 3
3 + 6 + -1b + -3b = 0

Combine like terms: 3 + 6 = 9
9 + -1b + -3b = 0

Combine like terms: -1b + -3b = -4b
9 + -4b = 0

Solving
9 + -4b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -4b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4b = 0 + -9
-4b = 0 + -9

Combine like terms: 0 + -9 = -9
-4b = -9

Divide each side by '-4'.
b = 2.25

Simplifying
b = 2.25

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