5-(b+3)=3(b+2)

Solution for 5-(b+3)=3(b+2) equation:

Simplifying
5 + -1(b + 3) = 3(b + 2)

Reorder the terms:
5 + -1(3 + b) = 3(b + 2)
5 + (3 * -1 + b * -1) = 3(b + 2)
5 + (-3 + -1b) = 3(b + 2)

Combine like terms: 5 + -3 = 2
2 + -1b = 3(b + 2)

Reorder the terms:
2 + -1b = 3(2 + b)
2 + -1b = (2 * 3 + b * 3)
2 + -1b = (6 + 3b)

Solving
2 + -1b = 6 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
2 + -1b + -3b = 6 + 3b + -3b

Combine like terms: -1b + -3b = -4b
2 + -4b = 6 + 3b + -3b

Combine like terms: 3b + -3b = 0
2 + -4b = 6 + 0
2 + -4b = 6

Add '-2' to each side of the equation.
2 + -2 + -4b = 6 + -2

Combine like terms: 2 + -2 = 0
0 + -4b = 6 + -2
-4b = 6 + -2

Combine like terms: 6 + -2 = 4
-4b = 4

Divide each side by '-4'.
b = -1

Simplifying
b = -1