5-(c-4)=3(n+2)

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Solution for 5-(c-4)=3(n+2) equation:


Simplifying
5 + -1(c + -4) = 3(n + 2)

Reorder the terms:
5 + -1(-4 + c) = 3(n + 2)
5 + (-4 * -1 + c * -1) = 3(n + 2)
5 + (4 + -1c) = 3(n + 2)

Combine like terms: 5 + 4 = 9
9 + -1c = 3(n + 2)

Reorder the terms:
9 + -1c = 3(2 + n)
9 + -1c = (2 * 3 + n * 3)
9 + -1c = (6 + 3n)

Solving
9 + -1c = 6 + 3n

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1c = 6 + -9 + 3n

Combine like terms: 9 + -9 = 0
0 + -1c = 6 + -9 + 3n
-1c = 6 + -9 + 3n

Combine like terms: 6 + -9 = -3
-1c = -3 + 3n

Divide each side by '-1'.
c = 3 + -3n

Simplifying
c = 3 + -3n

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