5-(m-4)=2m+3(m-1)

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Solution for 5-(m-4)=2m+3(m-1) equation:



5-(m-4)=2m+3(m-1)
We move all terms to the left:
5-(m-4)-(2m+3(m-1))=0
We get rid of parentheses
-m-(2m+3(m-1))+4+5=0
We calculate terms in parentheses: -(2m+3(m-1)), so:
2m+3(m-1)
We multiply parentheses
2m+3m-3
We add all the numbers together, and all the variables
5m-3
Back to the equation:
-(5m-3)
We add all the numbers together, and all the variables
-1m-(5m-3)+9=0
We get rid of parentheses
-1m-5m+3+9=0
We add all the numbers together, and all the variables
-6m+12=0
We move all terms containing m to the left, all other terms to the right
-6m=-12
m=-12/-6
m=+2

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