5-(n-4)=-3(n+2)

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Solution for 5-(n-4)=-3(n+2) equation: 



5-(n-4)=-3(n+2)

We move all terms to the left:

5-(n-4)-(-3(n+2))=0

We get rid of parentheses

-n-(-3(n+2))+4+5=0



We calculate terms in parentheses: -(-3(n+2)), so:

-3(n+2)

We multiply parentheses

-3n-6

Back to the equation:

-(-3n-6)



We add all the numbers together, and all the variables

-1n-(-3n-6)+9=0

We get rid of parentheses

-1n+3n+6+9=0

We add all the numbers together, and all the variables

2n+15=0

We move all terms containing n to the left, all other terms to the right

2n=-15

n=-15/2

n=-7+1/2

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