5-(n-4)=3(n+2)0

Solution for 5-(n-4)=3(n+2)0 equation:

Simplifying
5 + -1(n + -4) = 3(n + 2) * 0

Reorder the terms:
5 + -1(-4 + n) = 3(n + 2) * 0
5 + (-4 * -1 + n * -1) = 3(n + 2) * 0
5 + (4 + -1n) = 3(n + 2) * 0

Combine like terms: 5 + 4 = 9
9 + -1n = 3(n + 2) * 0

Reorder the terms:
9 + -1n = 3(2 + n) * 0

Reorder the terms for easier multiplication:
9 + -1n = 3 * 0(2 + n)

Multiply 3 * 0
9 + -1n = 0(2 + n)

Anything times zero is zero.
9 + -1n = 0(2 + n)

Solving
9 + -1n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1n = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1n = 0 + -9
-1n = 0 + -9

Combine like terms: 0 + -9 = -9
-1n = -9

Divide each side by '-1'.
n = 9

Simplifying
n = 9