5-(n-4)=3*(4+2)

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Solution for 5-(n-4)=3*(4+2) equation: 



5-(n-4)=3(4+2)

We move all terms to the left:

5-(n-4)-(3(4+2))=0

We add all the numbers together, and all the variables

-(n-4)+5-(36)=0

We add all the numbers together, and all the variables

-(n-4)-31=0

We get rid of parentheses

-n+4-31=0

We add all the numbers together, and all the variables

-1n-27=0

We move all terms containing n to the left, all other terms to the right

-n=27

n=27/-1

n=-27

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